![]() |
|
|||||||
| RSS Feeds Forum and Archived Posts This is a source of news and topics from RSS Feeds. RSS feeds pull data from other sites so they can be viewed on this site. There are also posts in here from past members for reference only! |
|
|
#1 (permalink) |
|
Fisherman
Join Date: Jun 2007
Posts: 59
Rep Power: 12
![]() |
A person fishing hooks a 7.0-kg fish on a line that can only sustain a maximum of 38 N of force before breaking. At one point while reeling in the bass, it fights back with a force of 41 N. What is the minimum acceleration with which you must play out the line during this time in order to keep the line from breaking?
|
|
|
|
| Sponsored Links |
|
|
#2 (permalink) |
|
Fishing King
Join Date: Apr 2007
Location: Ohio
Posts: 431
Rep Power: 43
![]() |
The fish fights back with a force of 41 N and the line can sustain only 38 N before being in danger of breaking. This 38 N represents the maximum force you can exert to restrain the fish, the remaining 3 N being taken up by the acceleration of the fish away from you. Using F = ma, this represents an accelaration of 3 N / 7.0 kg = 0.43 m/sec^2.
|
|
|
|
![]() |
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | |
| Display Modes | |
|
|